double y1 = 0; double y2 = 0; double i = 0.025; double n = 2; double h1 = 2000; double h2 = 4000; y1 = Math.pow((1 + i), n) * h1; y2 = Math.pow((1 + i), n) * h2; double result = y1 + y2; System.out.println(result); I want the result as "6303.749999999999" but it gives me "6303.75". How can i solve it?
correct result should be (and it is) 6303.750000000000017069679003611781820568916563219777423023367655509563911228609889292329171439632773399353027343750000
Try to give a look at the BigDecimal class.
BigDecimal i = new BigDecimal(0.025); int n = 2; BigDecimal h1 = new BigDecimal(2000); BigDecimal h2 = new BigDecimal(4000); BigDecimal y1 = ((BigDecimal.ONE.add(i)).pow(n)).multiply(h1); BigDecimal y2 = ((BigDecimal.ONE.add(i)).pow(n)).multiply(h2); BigDecimal result = y1.add(y2); System.out.println(result.toEngineeringString()); The problem is that you are calculating the value 6303.75. if you add a statement where you subtract the value 0.000000000001 from the variable result then you will get the expected value 6303.749999999999.
The below code changes demonstrate how you can instead calculate 6303.749999999999:
public static void main(String[] args){ double y1 = 0; double y2 = 0; double i = 0.025; double n = 2; double h1 = 2000; double h2 = 4000; y1 = Math.pow((1 + i), n) * h1; y2 = Math.pow((1 + i), n) * h2; double result = y1 + y2; result -= (double)0.000000000001; // this line is the key to calculating the expected result System.out.println(result); } Output:
6303.749999999999
6303.749999999999?