How to parse tags in java

Question

Response from server is like this:

<oob> <type>screen</type> <value>idle</value> <action>show</action> </oob> <oob> <type>schedule</type> <action>show</action> </oob>

I want to put all the tags as key and value inside tag as value. Numbers of tags and tag types are not known. I want something like this:

//for first string from server public HashMap<String, String> response = new HashMap<String, String>(); response.put("type","screen"); response.put("value","idle"); response.put("action","show"); //for second string response.put("type","schedule"); response.put("action","show");

There should be the logic to parse the string:

if(server_response.contains("<oob>")){ while(!endof server_response) response.put("?","?"); }

How to parse server response in that format?

An XML parser. Maybe the old DOM one, maybe pick it apart with XPath, maybe use JAXB, but basically, Java XML parsing. — David Ehrmann
– David Ehrmann, Commented Oct 28, 2015 at 4:12
Do you really get back malformed XML (in this case, there isn't a single root element)? — David Ehrmann
– David Ehrmann, Commented Oct 28, 2015 at 4:35

Jose · Accepted Answer · 2015-10-28 06:01:24Z

Use an XML parsing API, DOM API is one of the easiest to use but you will need to convert the string to a Document first.

You can convert the whole string to Node objects, using a loop, you can one by one check the expected elements for each (s) and put it to a collection.

Here's some code sample you can try:

DocumentBuilderFactory buildderfactory= DocumentBuilderFactory.newInstance(); DocumentBuilder db =buildderfactory.newDocumentBuilder(); Document docXml = db.parse(new InputSource( new StringReader( yourxml ))); NodeList list = docXml.getElementsByTagName("oob"); for (int i=0; i<list.getLength(); i++){ System.out.println(i); Node n = list.item(i); Node child =n.getFirstChild(); while(child!=null){ System.out.println(child.getNodeName()); System.out.println(child.getFirstChild().getNodeValue()); child= child.getNextSibling(); } }

Kumaresan Perumal · Accepted Answer · 2015-10-28 04:33:32Z

import java.io.File; import javax.xml.parsers.DocumentBuilderFactory; import javax.xml.parsers.DocumentBuilder; import org.w3c.dom.Document; import org.w3c.dom.NodeList; import org.w3c.dom.Node; import org.w3c.dom.Element; public class DomParserDemo { public static void main(String[] args){ try { File inputFile = new File("input.txt"); DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder dBuilder = dbFactory.newDocumentBuilder(); Document doc = dBuilder.parse(inputFile); doc.getDocumentElement().normalize(); System.out.println("Root element :" + doc.getDocumentElement().getNodeName()); NodeList nList = doc.getElementsByTagName("student"); System.out.println("----------------------------"); for (int temp = 0; temp < nList.getLength(); temp++) { Node nNode = nList.item(temp); System.out.println("\nCurrent Element :" + nNode.getNodeName()); if (nNode.getNodeType() == Node.ELEMENT_NODE) { Element eElement = (Element) nNode; System.out.println("Student roll no : " + eElement.getAttribute("rollno")); System.out.println("type : " + eElement .getElementsByTagName("type") .item(0) .getTextContent()); System.out.println("value : " + eElement .getElementsByTagName("value") .item(0) .getTextContent()); System.out.println("action: " + eElement .getElementsByTagName("action") .item(0) .getTextContent()); } } } catch (Exception e) { e.printStackTrace(); } } }

have a look at this link too. http://www.tutorialspoint.com/java_xml/java_dom_parse_document.htm

we don't know the tag name itself. I want both tag name and tag value. Also the number of tags are not fixed.
okay. fine.. look at this too.stackoverflow.com/questions/24446849/parse-xml-without-tagname

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