Why it is a StackOverFlow Exception?

Question

Why following code throws StackoverflowException?

class Foo { Foo foo = new Foo(); } class Program { static void Main(string[] args) { new Foo(); } }

because each instance of Foo creates and instance of Foo which creates an instance of Foo.... — juharr
– juharr, Commented Oct 30, 2015 at 12:55
Foo creates an instance of itself during initialization. That's infinite recursion. — plalx
– plalx, Commented Oct 30, 2015 at 12:57
Every new object is created on a stack. In your case you create infinite amount of objects and your application runs out of memory. — S K
– S K, Commented Oct 30, 2015 at 13:00
[needed] What is a StackOverflowException and how do I fix it? :) — Soner Gönül
– Soner Gönül, Commented Oct 30, 2015 at 13:03
'StackOverflowException' is thrown when is infinite recursion is started, or big/deep enough to exceed stack size. — Marko Krizmanic
– Marko Krizmanic, Commented Oct 30, 2015 at 13:19

Carter · Accepted Answer · 2024-02-05 19:31:12Z

In Main you create a new Foo object, invoking its constructor. Inside the Foo constructor, you create a different Foo instance, again invoking the Foo constructor.

This leads to infinite recursion and a StackOverflowException being thrown.

Dmitrii Bychenko · Accepted Answer · 2015-10-30 12:57:38Z

Well, let´s see:

Program runs main which executes new Foo();;
new Foo() creates new Foo instance, including Foo foo field
Foo foo = new Foo();executes new Foo (go to step 2)

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