how to get the next hour's date string in bash

Question

I 'm using bash I have a date string now, for example:

2015111301

(yyyymmddHH)

how to get the date string of next hour? that is:

2015111302

@Ashish, yes, I know how to get the format, the question was meant for the OP. — asimovwasright
– asimovwasright, Commented Nov 14, 2015 at 9:51

Cyrus · Accepted Answer · 2015-11-14 10:47:56Z

3

Try this:

in="2015111301" out="$(date -d "${in:0:8} ${in:8:2}:00:00 +1hour" '+%Y%m%d%H')" echo "$out"

Output:

2015111302

answered Nov 14, 2015 at 9:37

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3 Comments

why I am getting 2015111306 output in cygwin

I don't know. Tested with bash 4.2.8 and date from GNU coreutils 8.5.

I am getting same output in Ubuntu 15 LTS now

Ashish · Accepted Answer · 2015-11-14 09:44:16Z

This below script worked for me

#!/bin/bash tempval=$(echo 2015111301 | sed 's/\(.\{8\}\)/\1 /g') tempval=$(echo "$tempval 1 hour") date -d "$tempval" +%Y%m%d%H