How to create array of type[]? [duplicate]

Question

How to initialize the array of data types in System.Type Datatype

This sample code i am trying

Type[] coltypes = {string, string, string, string, string, string };

after I found the solution in this link i am able to understand the problem

Solution for this : Type[] coltypes = {typeof(string),typeof(int),typeof(double),typeof(string)};

poke · Accepted Answer · 2015-11-19 12:22:42Z

You need to use typeof() to get the type object for a type:

Type[] coltypes = new Type[] { typeof(string), typeof(int), typeof(double) };

Note that using the typeof expression is interpreted by the compiler and gets the type object at compile-time.

Soner Gönül · Accepted Answer · 2015-11-19 12:22:55Z

Because string is not System.Type itself. You can use typeof operator to generate it's System.Type.

You can use;

Type[] coltypes = { typeof(string), typeof(string), typeof(string), typeof(string), typeof(string), typeof(string) };

C. Knight · Accepted Answer · 2015-11-19 12:24:12Z

You're missing a comma for one thing,

Type[] coltypes = { typeof(string), typeof(string), typeof(string), typeof(string), typeof(string), typeof(string) };

3 Answers 3