Django: admin login with parameter

Question

I want to have my custom "/login" page. So in settings.py I did a simple LOGIN_URL = '/login'. But before doing it, I want to develop all other more complex pages. I found a simple but very effective hack like this:

urlpatterns = [ # blabla url(r'^admin/', include(admin.site.urls)), url(r'^login/$', RedirectView.as_view( url=reverse_lazy('admin:login'))), # blabla ]

This means: when the user is not connected he/she is redirected to /login. In the urls, /login is converted to 'admin:login' which is admin/login. This is a "double" redirect. Everthing works fine except this:

origin URL: "/my_jobs"
redirected to "login?next=/my_jobs"
redirected to "/admin/login"

So my problem is that I want do pass again the "next" parameter in the RedirectView. I found a lot about redirection and custom login, but not something about that on stackoverflow (this is not a duplicate).

Alasdair · Accepted Answer · 2015-12-15 12:05:31Z

You can set query_string to True, so that query strings are appended to the URL.

RedirectView( url=reverse_lazy('admin:login'), query_string=True, # You might want to set permanent=False, # as it defaults to True for Django < 1.9 permanent=False, )

Note that Django comes with a built in login view. You can enable it by adding the URL pattern and a simple template, which isn't much more work than your code above.

It's that simple... i've been fighting for that for 2 hours now... thank you very much
I would use the built in logout view rather than trying to redirect to the admin logout view.

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