Righ way to pass interface address into bind

Question

Im working od UDP app and I'm not sure if I'm doing this right. I need to get address into addr.sin_addr.s_addr. Until now I just used addr.sin_addr.s_addr = htonl(INADDR_ANY) but I will need to set specific address goten from user. Am I doing it right when I use addr.sin_addr.s_addr = htonl(adresa)?

Full code:

int main(int argv, char **argc) { strcpy(adresa, "someadress"); int optval; struct sockaddr_in addr;//, incoming_addr; /* create socket */ sock = socket(PF_INET, SOCK_DGRAM, IPPROTO_UDP); if (sock < 0) { err("socket()"); } /* set reusable flag */ optval = 1; setsockopt(sock, SOL_SOCKET, SO_REUSEADDR, &optval, sizeof(optval)); /* prepare inet address */ memset(&addr, 0, sizeof(addr)); addr.sin_family = AF_INET; addr.sin_port = htons(port); if(strcmp(adresa, "-") == 0) { addr.sin_addr.s_addr = htonl(INADDR_ANY); /* listen on all interfaces */ } else { addr.sin_addr.s_addr = htonl(adresa); /* listen on all interfaces */ } if (bind(sock, (struct sockaddr*)&addr, sizeof(addr)) < 0) { err("bind"); } for(;;) { } return 0; }

dbush · Accepted Answer · 2016-01-14 19:42:20Z

The simplest way is with the inet_addr function, which can take an IPv4 address and convert it to an address in network byte order as an in_addr_t. This value can then be stored in sin_addr.s_addr:

addr.sin_addr.s_addr = inet_addr(adresa);

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