From HttpClient to HttpURLconnection

Question

I want to upgrade my code for posting a json. The first one implements HttpClient and it works fine! I tried to use the new implementation using HttpURLconnection and it doesn't work! I can't send any post request. What I'm missing?

public class AsyncPostBG extends AsyncTask<String, String, String> { private ProxyState mData = null; private String mName = null; public AsyncPostBG(ProxyState data, String name) { mData = data; mName = name; } @Override protected String doInBackground(String... params){ HttpParams httpParams = new BasicHttpParams(); HttpClient httpClient = new DefaultHttpClient(httpParams); HttpPost postMethod = new HttpPost(params[0]); postMethod.setHeader("Content-Type", "application/json; charset=utf-8"); postMethod.setHeader("Accept", "*/*"); postMethod.setHeader("Accept-Encoding", "gzip, deflate"); Gson gson=new Gson(); String json = gson.toJson(mData); try { postMethod.setEntity(new ByteArrayEntity(json.getBytes("UTF8"))); HttpResponse response = httpClient.execute(postMethod); StatusLine statusLine = response.getStatusLine(); } catch (UnsupportedEncodingException e){ } catch (Exception e) { } return json; } }

Here is my HttpURLConnection implementation:

private class AsyncStatePostBG extends AsyncTask<String, Void, String> { private ProxyObj mData = null; private String mName = null; public AsyncStatePostBG(ProxyObj data, String name) { mData = data; mName = name; } @Override protected String doInBackground(String... params) { Gson gson = new Gson(); String json = gson.toJson(mData); HttpURLConnection connection = null; try { URL object = new URL(ComURL + "api/state/" + mName); connection = (HttpURLConnection) object.openConnection(); connection.setDoOutput(true); connection.setDoInput(true); connection.setRequestMethod("POST"); connection.setRequestProperty("Content-Type", "application/json"); connection.setRequestProperty("Accept", "*/*"); connection.setRequestProperty("Accept-Encoding", "gzip, deflate"); connection.connect(); OutputStreamWriter streamWriter = new OutputStreamWriter(connection.getOutputStream()); streamWriter.write(json); streamWriter.flush(); streamWriter.close(); } catch (Exception exception) { return null; } return json; } }

mkyong.com/java/how-to-send-http-request-getpost-in-java this can help you. — Chirag Savsani
– Chirag Savsani, Commented Feb 1, 2016 at 8:35
You silently swallow all exceptions. However, they provide valuable input for diagnosing the problem. — Henry
– Henry, Commented Feb 1, 2016 at 8:35

Raja Jawahar · Accepted Answer · 2016-02-01 08:40:23Z

You can just goahead with this code, it works for me..

 URL url = new URL("Your URL"); HttpURLConnection httpsURLConnection = (HttpURLConnection)url.openConnection(); httpsURLConnection.setReadTimeout(15000); httpsURLConnection.setConnectTimeout(20000); httpsURLConnection.setDoInput(true); httpsURLConnection.setRequestProperty("Content-Type", "application/json"); //Method Type httpsURLConnection.setRequestMethod("POST" : "PUT"); OutputStream outputStream = httpsURLConnection.getOutputStream(); BufferedWriter bufferedWriter = new BufferedWriter(new OutputStreamWriter(outputStream, "UTF-8")); bufferedWriter.write("Your Params"); bufferedWriter.flush(); bufferedWriter.close(); outputStream.close(); httpsURLConnection.connect(); int mStatus = httpsURLConnection.getResponseCode();

Check the response code, and get the result like below

if (mStatus == 200 || mStatus == 201) return readResponse(httpsURLConnection.getInputStream()).toString();

Method for getting the response..

private static StringBuilder readResponse(InputStream inputStream) throws IOException, NullPointerException { BufferedReader r = new BufferedReader(new InputStreamReader(inputStream)); StringBuilder stringBuilder = new StringBuilder(); String line; while ((line = r.readLine()) != null) { stringBuilder.append(line); } return stringBuilder; }

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