Functional interface as argument of the same

Question

While exercising lambdas in Java 8, I came across the below functional interface.

@FunctionalInterface interface MyFunctional { void invokeSame(MyFunctional myFunc); }

Could you tell me how can I provide lambda expression for this Functional interface?

Alex - GlassEditor.com · Accepted Answer · 2016-02-09 02:13:38Z

2

The same way as any other one argument and void return type lambda:

MyFunctional f = myFunc -> {};

answered Feb 9, 2016 at 2:13

Alex - GlassEditor.com

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Majeed Siddiqui · Accepted Answer · 2016-02-09 10:32:43Z

Concept: Type checking in java 8 lambdas is done based on target (the function to which it is being passed as an argument).

Explanation: Generally a function is defined by 3 attributes:

Function Name.
Type and order of arguments passed.
Return type of function.

But while passing an lambda Java only checks for last two. So for above Functional Interface we need lambda with [first] argument type MyFunctional and return type void.

void doSomething(MyFunctional x) { ... ... x.invokeSame(...An object/lambda of type MyFunctional...) } To call this function doSomething(varName -> { ...someCode... })

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