1

I have file 1.php having a require_once for 2.php (both of them are in different folders). The issue I am having is that 1.php seems to magically include 2.php since the path for 2.php is not in 1.php. Just to be sure, I even added a set_include_path('.') before the require_once '2.php', but it still works... Is there something obvious I am missing or is this plain weird??

Edit:

//-- file 1.php //-- long list of requires... set_include_path('.'); echo get_include_path(); require_once '2.php';

The above works fine while 1.php and 2.php are in different folders.

Improve this question
7
  • Please be more specific on the locations of all the files involved. Commented Aug 23, 2010 at 9:49
  • Got any code you can add? It does seem odd. Commented Aug 23, 2010 at 9:50
  • @VolkerK - here we have only two files 1.php and 2.php and they are in two different locations.. @Kevin - added the code.. thanks for the comments.. Commented Aug 23, 2010 at 9:57
  • "different locations" like what? Like /home/www/lala/1.php and /var/temp/2.php ? Commented Aug 23, 2010 at 9:59
  • different locations like /var/www/test/1.php and /var/www/test/abcd/2.php... can you explain how that is relevant?? Commented Aug 23, 2010 at 10:01

5 Answers 5

Reset to default
2

There is some include magic in PHP, i've met it before.
Something autoload related, I believe.
It always looks in the folder where file with running class resides

Improve this answer
Sign up to request clarification or add additional context in comments.

2 Comments

hmmm.. this looks interesting... where do i start looking for any autoload magic???
@pinaki dunno, I was looking into source code lol :) In some PHP OOP manual probably, because autoload is OOP feature
1

Try echo get_include_path() after you set your empty include path, it may be set somewhere else (like in the web server config file).

Improve this answer

1 Comment

there was a typo in the description... i have tried putting an echo get_include_path().. it lists the set path (.) in my case..
1

Long shot but maybe one of the other included files changed the current working directory:

<?php echo 'cwd at the beginning of 1.php: ', getcwd(), "\n"; //-- file 1.php //-- long list of requires... set_include_path('.'); echo 'include_path: ', get_include_path(), " \n"; echo 'cwd: ', getcwd(), "\n"; require_once '2.php';
Improve this answer

2 Comments

require and include work with the current working dir when looking for files. So, if a script sets the cwd to the folder of 2.php (as VolkerK suggested), the seen behaviour would occur. Another option would be, that 1.php gets included by a script living in the folder of 2.php, so the cwd is there due to the initial invoke.
@ZeissS - i already did an echo getcwd() inside 2.php and that is not the case here...
1

For the sake of argument, if you put a 2.php in the same location as 1.php does the new file get included instead of the old one?

Can you tell use what the value of your open_basedir is?

Improve this answer

1 Comment

if i put them in the same place, it works fine.. open_basedir value in "no value"... i tried changing from 2.php to pinaki/2.php in the require_once and it failed... at last some sanity :)...
1

Perhaps you have a file with the same name as file 2 in the path of file 1.

Improve this answer

Comments

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.