Gulp and TS compilation

Question

I have defined task in my gulp file:

gulp.task('dev:build:scripts', function () { var tsResult = tsProject.src() .pipe(sourcemaps.init()) .pipe(ts(tsProject)); });

Which takes all of the scripts, and creates source maps to the static/dist. My tsProject:

var tsProject = ts.createProject('tsconfig.json', { outDir: paths.dist +'/app' });

And my tsconfig.json

{ "compilerOptions": { "target": "es5", "module": "system", "moduleResolution": "node", "sourceMap": true, "emitDecoratorMetadata": true, "experimentalDecorators": true, "removeComments": false, "noImplicitAny": false, "outDir": "static/dist/app" }, "exclude": [ "node_modules" ] }

However, after the gulp runs the project, it doesnt compile the JS and doesnt create sourcemaps - it only does so, when I make a change to any ts file. How can I fix this?

Amid · Accepted Answer · 2016-03-12 11:34:31Z

I think you forgot to actually write your results. Try this one:

gulp.task('dev:build:scripts', () => { var tsProject = ts.createProject('tsconfig.json'); var tsResult = tsProject.src() .pipe(sourcemaps.init()) .pipe(ts(tsProject)); return tsResult.js.pipe(sourcemaps.write()).pipe(gulp.dest(paths.dist +'/app')); });

that was it :) thanks! do you know if it is possible to run npm install as a gulp task?
Like this: npmjs.com/package/gulp-exec or this npmjs.com/package/gulp-shell ?

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