How convert a date from dd-mm-yy to mm-dd-yy
below is my code
<? $date= date('d-m-y'); echo date('m-d-Y',strtotime($date)); ?> but the result is : 09-10-2001
i need 09-01-2010
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5 Answers
This won't work:
date('m-d-y', strtotime($the_original_date)); If you have PHP 5.3, you can do:
$date = DateTime::createFromFormat('d-m-y', '09-10-01'); $new_date = $date->format('m-d-Y'); Otherwise:
$parts = explode('-', $original_date); $new_date = $parts[1] . '-' . $parts[0] . '-' . $parts[2]; 
3 Comments
bcosca
This will fail in certain situations because strtotime recognizes US English dates. 03-01-10 will be interpreted as March 1, 2010 not January 3, 2010.
Testadmin
this is my code <? $date= date('d-m-y'); echo date('m-d-Y',strtotime($date)); but the result is: 09-10-2001 i need 09-01-2010 thanks for your reply
jasonbar
Updated answer because it was entirely wrong. Thanks @stillstanding.
You can do:
$input = 'dd-mm-yy'; $a = explode('-',$input); $result = $a[1].'-'.$a[0].'-'.$a[2]; 1 Comment
Pramendra Gupta
$old_date = date($date); $old_date_timestamp = strtotime($old_date); $new_date = date('d-m-Y', $old_date_timestamp);
try this date("m-d-y", {your date variable})
Comments
If the format is always like above, this should work:
$pieces = explode("-", $yourTimestring); $timestamp = mktime(0,0,0,$pieces[1], $pieces[0], $pieces[2]); $newDateStr = date("m-d-y", $timestamp); Edit: True, just saw the answer from "codaddict" and yeah, if i alredy split it up you could also concatenate it directly ^^
Comments
You could use the sscanf function if you dont have PHP 5.3 available and make use of the argument swapping option:
$theDate = '01-02-03'; print join(sscanf($theDate, '%2$2s-%1$2s-%3$2s'), '-'); # output: 02-01-03 sscanf basically parses the provided string in an array based on the provided format, swapping the first matched argument (the day) with the second (the month), leaving the third one (year) untouched and then this array is joined again with the - as separator.
