Get value from future

Question

I have method

def seqAll: Future[Seq[User]] = dbConfig.run(users.result) def getAll: Seq[User] = Users.seqAll.map(a=>a)

second method actually returns Future[Seq[User]], but I want it to be just Seq[User]. How can I achieve that?

Possible duplicate of Accessing value returned by scala futures — ziggystar
– ziggystar, Commented Apr 12, 2016 at 9:24

Simon · Accepted Answer · 2016-04-12 08:58:11Z

You can use Await.result but that means making the Future blocking and not asynchronous which takes away the point of using a future. Of course, blocking might not be a problem for you.

If you do want to get the result in a non-blocking way you do

Users.seqAll.map(a=>a) onComplete { case Success(result) => // use result for something case Failure(t) => // Handle error }

Chris Martin · Accepted Answer · 2016-04-12 08:55:03Z

With Await.result:

import scala.concurrent.Await import scala.concurrent.duration.DurationInt def getAll: Seq[User] = Await.result(seqAll, 5.seconds)

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