I run a loop:
N = 10 alpha = 0.05 sigma = 0.01 for (i in 0:N){ Vt10[i] = ((sigma^2)/(alpha^2))*((N-i)+(2/alpha))*exp(-alpha*(N-i))-(1/(2*alpha))*exp(-2*alpha*(N-i))-(3/(2*alpha)) } However, Vt10 eventually outputs only 10 outcomes (doesn't include the first iteration, when i = 0). How can I create a vector that would include all 11 iterations?
Answer:
N = 10 alpha = 0.05 sigma = 0.01 Vt10 = numeric(11) ## this! for (i in 0:N){ Vt10[i+1] = ((sigma^2)/(alpha^2))*((N-i)+(2/alpha))*exp(-alpha*(N-i))-(1/(2*alpha))*exp(-2*alpha*(N-i))-(3/(2*alpha)) } Also, you need Vt10[i+1], because you loop from 0 to 10, while array index should be 1 to 11.
Comment:
Your code looks like C code. Not only you start index from 0, but also you write a loop for this task.
Try:
N = 10 alpha = 0.05 sigma = 0.01 i = 0:10 Vt10 = ((sigma^2)/(alpha^2))*((N-i)+(2/alpha))*exp(-alpha*(N-i))-(1/(2*alpha))*exp(-2*alpha*(N-i))-(3/(2*alpha)) In this situation, there is no need to predefine a vector. R knows you are performing element-wise computation, and will automatically assign a length-11 vector for Vt10.