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i need to write a bat file which can give me the last names of files in a network folder.The names has the specific pattern.simmilar to this pattern.

Deepak.DEMO.yyyymmdd mcapatna.POWERHOUSE.yyyymmdd

where Deepak.DEMO & mcapatna.POWERHOUSE are fixed but yyyymmdd is variable depends on the year month & date.

  1. I have to find this yyyymmdd using batch programming &
  2. if possible than compare it with current date.if it is today date then proceed further otherwise move these file to different folder. I tried a lot but i am unable to do it.could someone please help me.
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  • Please put the code you have tried so far with your question... For getting the files with "yyyymmdd" given, you can use the dir /b *.<yyyymmdd> command. Check the /b switch at dir /?. Commented Jun 2, 2016 at 19:41

1 Answer 1

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for %%i in (Deepak.DEMO.* mcapatna.POWERHOUSE.*) do echo %%~xi

See here for a possible solution to get the date in the same format. Comparing for equality should be trivial.

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