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var $slideObj = $('#slideshow .slideItem'); var num = 10;

I got that code and I want to find the nth-child of the "$slideObj" element. The code below works but I want to use the variable instead of finding the element again.

var $currentSlideObj = $('#slideshow .slideItem:nth-child(' + num + ')');

What I want is the following, $slideObj.nth-child(num); I have tried the following below.

$slideObj.find(':nth-child('+num+')'); $slideObj.eq(num);
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1 Answer 1

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You actually already have all the "children" in your $slideObj.

You need to use .filter rather than .find (filter the current result set, not look deeper in the tree).

$slideObj.filter(':nth-child(' + num + ')');
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1 Comment

Worked! Keep forgetting about the filter method.

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