How to find square root of large numbers in Python?

Question

I am trying to find out the square root of a number. But the numbers are large. Python gives the error

OverflowError: int too large to convert to float

My code is here:

number=pow(255,200)-10000000 sqrt=math.sqrt(number)

i tried it with the decimal class but it doesn't work. How to handle these large numbers in python?

the Decimal class it can handle it with its .sqrt method: (pow(Decimal(255),200)-10000000).sqrt() = Decimal('4.508354347658170012443202806E+240') — Copperfield
– Copperfield, Commented Aug 20, 2016 at 3:53

Sun · Accepted Answer · 2016-08-20 04:01:36Z

1

import math pow(10, 1/2 * math.log10(pow(255,200)-10000000))

The result is: 4.508354347658245e+240

answered Aug 20, 2016 at 4:01

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1 Comment

Its working fine but it cannot assign to a variable.