Get called class name in Another class

Question

we have one class

class A { // I am using class B here public function whatever() { $class_b = new B; $class_b->show_caller(); } }

and other

class B { public function show_caller() { // show me the caller class (should output "A") } }

I need to get the caller class name. P.S. Inheritance is not an option!

Well, I know the architecture is bad, but project it's pretty big and i haven't time to refactor all of it. I just can't use Inheritance. — remtsoy
– remtsoy, Commented Aug 21, 2016 at 15:11

John Conde · Accepted Answer · 2016-08-21 15:10:29Z

1

Pass class A as a parameter to B::show_caller() and output it's class name using get_class():

class A { // I am using class B here public function whatever() { $class_b = new B; $class_b->show_caller($this); } } class B { public function show_caller($class) { echo get_class($class); } }

answered Aug 21, 2016 at 15:10

John Conde

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2 Comments

John Conde Over a year ago

That doesn't mean anything. How is it supposed to be dynamic? How wouldn't solution work for you?

jaro1989 Over a year ago

I think he mean that $class_b->show_caller($class_b); will return B, not A. But it's really interesting to find solution without parameters

jaro1989 · Accepted Answer · 2016-08-21 22:44:05Z

We can't provide the knowledge about of where your method is executing to method's class without parameters. Late static binding will work only with inheritance, so it's not your case. The only approach, I can give you, is to use your IDE ability to find method usage in your project (ctrl+mouse1 in PhpStorm). If you're not using any IDE - it's a time to start.

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