I have what will probably become a simple question to answer.
I have an array called emails .
I'm iterating over them using emails.each do |email| .
What I want to say is:
# if array index is 0, do this. I've tried if email.index == 0 .
I've tried to find a solution, but can't for the life of me find it. As it's only one argument, I'd like to avoid a case statement.
try each_with_index
emails.each_with_index do |email, index| if index == 0 # do something end end 
Like the others answered, if you need the enumeration:
emails.each.with_index([startindex]) do |email, index| eg
emails.each.with_index(1) do |email, index| But if you only need that element then you can act upon directly like this
emails.first what is the same as
emails[0] Like people said before, each_with_index is a good choice. However, if you want to start your index from anything else than 0, there's a better way (note that the dot is on purpose, we are calling Enumerator#with_index here):
emails.each.with_index(1) do |email, index| # ... end You can use .each_with_index it will provide you the index of each element in the array.
for example
['a','b','c'].each_with_index {|item, index| puts "#{item} has index #{index}" } output
a has index 0 b has index 1 c has index 2 
Ok. If you looking for index 0 - you can use emials[0] or emails.at(0), or you can iterate emails -
emails.each_with_index do |val, index| if index == 0 # something end end It's all.
