string words[5]; for (int i = 0; i < 5; ++i) { words[i] = "word" + i; } for (int i = 0; i < 5; ++i) { cout<<words[i]<<endl; } I expected result as :
word1 . . word5 Bu it printed like this in console:
word ord rd d Can someone tell me the reason for this. I am sure in java it will print as expected.
C++ is not Java.
In C++, "word" + i is pointer arithmetic, it's not string concatenation. Note that the type of string literal "word" is const char[5] (including the null character '\0'), then decay to const char* here. So for "word" + 0 you'll get a pointer of type const char* pointing to the 1st char (i.e. w), for "word" + 1 you'll get pointer pointing to the 2nd char (i.e. o), and so on.
You could use operator+ with std::string, and std::to_string (since C++11) here.
words[i] = "word" + std::to_string(i); BTW: If you want word1 ~ word5, you should use std::to_string(i + 1) instead of std::to_string(i).
to_string(i + 1) not just i
words[i] = "word" + (String)i;I prefer the following way:
string words[5]; for (int i = 0; i < 5; ++i) { stringstream ss; ss << "word" << i+1; words[i] = ss.str(); } 
to_stringfunction.