<a ui-sref="apps.service" href="#/apps/service"> <i class="glyphicon glyphicon-list icon zoom-icon text-info-dker"></i> <span class="font-bold"> Service</span> </a> How can I locate the element?
driver.findElement(By.partialLinkText("service")).click(); driver.findElement(By.xpath("ui[href$=services]")); partialLinkText is case sensitive. Try
driver.findElement(By.partialLinkText("Service")).click(); The element is in <a> tag, not <ui> tag
driver.findElement(By.xpath(".//a[href*='services']")); You should try using xpath with WebDriverWait to wait until element visible and enable as below :-
new WebDriverWait(driver, 10).until(ExpectedConditions.elementToBeClickable(By.xpath(".//a[contains(.,'Service')]"))).click(); It is better to use contains in to locate element in this xpath. The below xpath will be accurate.
driver.findElement(By.xpath("//a/span[contains(text(),'Service')]")
This XPath,
//a[normalize-space() = 'Service'] will select all a elements whose normalized string value equals "Service" -- perfect for the example you show.
Be wary of solutions based upon contains() as they will also match strings that include additional leading or trailing text, which may or may not be what you want.
