Rails 4 Error: NoMethodError / undefined method

Question

Hey there,
I am fairly new to Rails and I've managed to create a Favorite controller for my Items(Tools) and Users, which works totally fine.
Now I am trying to do the same just in that user module. So users are able to favorite other users.

I played around, and came up with this:

I am getting this error in the browser when accessing /users/index view:

NoMethodError in Users#index undefined method `favorite_user_path' for #<#<Class:0x8ca77b8>:0x8ca50b8>

Here is my code:

app/models/favorite_user.rb

class FavoriteUser < ActiveRecord::Base belongs_to :c_user_id belongs_to :user_id end

app/models/user.rb

class User < ActiveRecord::Base # Include default devise modules. Others available are: # :confirmable, :lockable, :timeoutable and :omniauthable devise :database_authenticatable, :registerable, :recoverable, :rememberable, :trackable, :validatable has_many :tools # Favorite tools of user has_many :favorite_tools # just the 'relationships' has_many :favorites, through: :favorite_tools, source: :tool # the actual tools the user favorites # Favorite users of user has_many :favorite_users # just the 'relationships' has_many :userfavorites, through: :favorite_users, source: :user # the actual users the user favorites has_many :userfavorited_by, through: :favourite_users, source: :user # the actual users favoriting a user mount_uploader :avatar_filename, AvatarUploader end

app/controllers/users_controller.rb

class UsersController < ApplicationController before_action :find_user, only: [:show, :favorite] # Add and remove favorite recipes # for current_user def userfavorite type = params[:type] if type == "favorite" current_user.userfavorites << @user elsif type == "unfavorite" current_user.userfavorites.delete(@user) else # Type missing, nothing happens redirect_to :back, notice: 'Nothing happened.' end end def index @users = User.all end def show @tools = Tool.where(user_id: @user).order("created_at DESC") @tool = Tool.find(1) end private def find_user @user = User.find(params[:id]) end end

app/views/users/index.html.haml

- @users.each do |user| = image_tag gravatar_for user if user.use_gravatar == true = image_tag user.avatar_filename.url if user.use_gravatar == false %h2= link_to user.username, user %p= link_to "Favorite", favorite_user_path(user, type: "favorite"), method: :get %p= link_to "Unfavorite", favorite_user_path(user, type: "unfavorite"), method: :get

app/config/routes.rb

resources :users, only: [:index, :show, :userfavorite] do get :userfavorite, on: :member end

I hope the provided data is enough, if not please tell me. I'm grateful for all Your replies.

Your route is userfavorite. So that'd be userfavorite_user_path. — Ven
– Ven, Commented Sep 5, 2016 at 16:21
@Ven That works, don't know how I missed that - never copy code from what you've done already and then change something I guess! A question though on the user model: Is it generally possible what I am doing there? Just because I am linking to a model which does not exist, but instead I would like to link to the exact same model I am linking from. Can I just delete this piece of code: 'source: :user'? — Gugubaight
– Gugubaight, Commented Sep 5, 2016 at 16:32

Sunil Antony · Accepted Answer · 2016-09-05 16:22:45Z

1

You haven't declared any such path in the routes file. As per your routes file you can use named path like

userfavorite_user_path(user_id)

answered Sep 5, 2016 at 16:22

Sunil Antony

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3 Comments

Gugubaight Over a year ago

That works, don't know how I missed that - never copy code from what you've done already and then change something I guess! A question though on the user model: Is it generally possible what I am doing there?

Gugubaight Over a year ago

Just because I am linking to a model which does not exist, but instead I would like to link to the exact same model I am linking from. Can I just delete this piece of code: 'source: :user'?

Ven Over a year ago

There's a close reason on SO that's "simple typographical error". Answering such questions to get some rep is... well.

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