fgetc does not identify EOF [duplicate]

Question

The program below runs fine on various Solaris/Linux flavours, but not on AIX. However, if I replace while(c!=EOF) with while(c!=0xff) on AIX it runs completely fine.

Any thoughts? I checked the fgetc man page on AIX, and it should return the EOF constant!

#include <stdio.h> #include<unistd.h> #include <string.h> int main() { char c; FILE *fp; fp = fopen("a.txt", "r"); c=fgetc(fp); while(c!=EOF) { c=fgetc(fp); printf("%d",c); } fclose(fp); return 0; }

It seems that AIX has chars that are unsigned

Antti Haapala
– Antti Haapala

2018-05-25 07:46:06 +00:00
Commented May 25, 2018 at 7:46 — Antti Haapala
– Antti Haapala, Commented May 25, 2018 at 7:46

codaddict · Accepted Answer · 2013-10-16 12:58:32Z

17

The return value of fgetc is int not char. So change

char c;

to

int c;

edited Oct 16, 2013 at 12:58

user283145

answered Oct 20, 2010 at 11:26

codaddict

457k83 gold badges501 silver badges537 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

fgetc does not identify EOF [duplicate]

1 Answer 1

Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Linked

Related