Python Requests ignoring time outs

Question

I'm trying to make some kind of a scanner with python (just for fun)

it will send a get request to an random ip and see if there is any answer the problem is that every time that the connection fails the program will stop running . this is the code

import time import requests ips = open("ip.txt", "r") for ip in ips: r = requests.get(url="http://"+ip+"/",verify=False) print(r.status_code) time.sleep(0.5)

this is what i get by trying just a random ip :

requests.exceptions.ConnectionError: HTTPConnectionPool(host='177.0.0.0', port=80): Max retries exceeded with url:

Jed Fox · Accepted Answer · 2016-10-04 23:25:13Z

2

This is throwing an error. To protect against this, use a try/except statement:

for ip in ips: try: r = requests.get(url="http://"+ip+"/",verify=False) print(r.status_code) except requests.exceptions.RequestException as e: print('Connecting to ip ' + ip + ' failed.', e) time.sleep(0.5)

edited Oct 4, 2016 at 23:25

answered Oct 4, 2016 at 19:29

Jed Fox

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5 Comments

tdelaney Over a year ago

catching requests.exceptions.RequestException would capture more probems.

kylieCatt Over a year ago

Nitpick: Adding from requests.exceptions import RequestConnection, ConnectionError would be better for readability.

tdelaney Over a year ago

@IanAuld - not necessarily. Discarding the namespace leaves future readers guessing which one you are talking about.

tdelaney Over a year ago

ConnectionError inherits from RequestException so you only need the more general one.

Jed Fox Over a year ago

Thanks again @tdelaney

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