using no namespace in xpath expression

Question

In an XSLT stylesheet, I have set xpath-default-namespace to match the input document that the stylesheet processes. The output document is in the no namespace.

For example, the xsl:stylesheet element has xpath-default-namespace specified:

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xpath-default-namespace="http://my.example.com/" >

Within the transform, I am building elements with no namespace, and I need to match on these elements as well. For now, I use constructs such as:

<xsl:variable name="vCustomElement" as="element()"> <some_element> <!-- element content --> </some_element> </xsl:variable> <xsl:apply-templates select="$vCustomElement" mode="something" /> . . <xsl:template match="*:some_element" mode="something"> ... <xsl:sequence select="." /> ... </xsl:template>

This works, but I am curious, is there a way for me to specify no namespace as a prefix in an xpath expression? The above only works, as its matching all namesapces including the no namespace

Michael Kay · Accepted Answer · 2016-11-15 15:44:47Z

In XSLT/XPath 3.0 you can write match="Q{}local" to match a no-namespace element, regardless of the current setting of xpath-default-namespace.

There's no way to do this in 2.0, other than resetting xpath-default-namespace, which you can do on any element with local scope.

yas · Accepted Answer · 2016-11-15 14:33:15Z

The following works, although, I am still curious if there is someway to specify the no namesapce as a prefix in the match expression

<xsl:template match="some_element" mode="something" xpath-default-expression=""> ... <xsl:sequence select="." /> ... </xsl:template>

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