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I am trying to read the content of the folder of my Java EE Spring application, but it always return me null. The folder I want is under src/main/resources folder and it`s called context. I try doing it this way : 

File file = new File("src/main/resources/context")

But it always return me null for file.

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  • file can only be a existing file and not a directory. 10 secs of google and i found this docs.oracle.com/javase/tutorial/essential/io/dirs.html#listdir Commented Nov 24, 2016 at 8:25
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    Directory should not be a problem for the java.io.File object. In fact, even if the file or folder does not exist, file` will get assigned a valid non-null object. Commented Nov 24, 2016 at 8:28
  • i would suggest, get current folder path using something like: System.getProperty("user.dir"); and then append your path of the folder to the path return by this getProperty method. Commented Nov 24, 2016 at 8:32
  • src/main/resources implies that you're using Maven to build your application, and that we're actually talking about a folder that is a project resources. To list its content, refer to the linked question -- you can't use the File approach. Commented Nov 25, 2016 at 22:41

1 Answer 1

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You can use one of the following:

 File file = new File("src/main/resources/context"); String[] list = file.list(); // returns an array of all file names in the context folder.

OR

 File file = new File("src/main/resources/context"); File[] listFiles = file.listFiles(); // returns an array of all "file objects" for all files in the context folder.

Hope this helps!

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