How would I generate random numbers to 2 decimal places in the range (0, 0.1]. My code so far is generating numbers with two decimal places in the range [0, 0.1]:
radius = round(random.uniform(0, 0.1), 2) 
- Not sure what is wrong here. What's the error there?Ali Gajani– Ali Gajani2016-11-24 17:57:03 +00:00Commented Nov 24, 2016 at 17:57
- 2@AliGajani They want to exclude 0.00Nayuki– Nayuki2016-11-24 17:57:44 +00:00Commented Nov 24, 2016 at 17:57
- radius = round(random.uniform(0.01, 0.1), 2)Januka samaranyake– Januka samaranyake2016-11-24 17:59:26 +00:00Commented Nov 24, 2016 at 17:59
- 2@Janukasamaranyake Note that using round() creates a bias, because 0.01 is less likely to occur than 0.02Nayuki– Nayuki2016-11-24 18:00:05 +00:00Commented Nov 24, 2016 at 18:00
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3 Answers
Perhaps the easiest way to solve your problem is to think in terms of integers, not floating-point numbers.
You basically want possible random numbers like 0.01, 0.02, 0.03, ..., 0.09, 0.10.
First you generate an integer between 1 to 10 inclusive, then you divide by 100.0 to get a floating-point number.
Here is the code:
x = random.randint(1, 10) y = x / 100.0 Documentation: random.randint(a, b)
radius = round(random.uniform(0.005, 0.10499999999999), 2) print(radius) you also need to extend the range of the sampled values to make sure that the probability of selecting the edge numbers 0.01 and 0.1 is the same as that of any other number in the desired range. otherwise, they will be sampled with half of probability of other numbers. I assume that round function rounds up i.e. 0.105 would end up as 0.11 not 0.10.
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Try subtract random value from max value as uniform includes low, but excludes high then you will get values from 0 to max excluding low and including high:
radius = round(0.1-random.uniform(0, 0.1), 2) 
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Nayuki
This still produces the same distribution, and still produces 0.00