hashlib.sha256 yields unexpected result

Question

I'm trying to implement the following steps in Python:

Compressed public key: 02F840A04114081690223B7069071A70D6DABB891763B638CC20C7EC3BD58E6C86 SHA-256 of public key yields: cb05d0fd5e76ba8ea88323fc5d3eefd09a78d8e2a5fd4955307b549657a31330

This step is fairly simple, so I wrote this piece of code to see if it works as planned:

from binascii import hexlify from hashlib import sha256 master_key = hexlify("02F840A04114081690223B7069071A70D6DABB891763B638CC20C7EC3BD58E6C86") print(sha256(master_key).hexdigest())

However, this doesn't yield the expected result. Instead it gives me:

cee4b5650664b11623675d0371ab9dd1e3478758a95b189e54ecf8b7bdd7ba2d

Using the string without hex-encoding it first doesn't yield the correct result either. Any ideas?

You're using hexlify() to convert the hex representation of the key to hex. It's already in hex. You probably want to use unhexlify(). — kindall
– kindall, Commented Jan 9, 2017 at 19:22

hiro protagonist · Accepted Answer · 2017-01-09 19:23:56Z

you want to unhexlify your hexadecimal representation:

from binascii import unhexlify from hashlib import sha256 master_key = unhexlify("02F840A04114081690223B7069071A70D6DABB891763B638CC20C7EC3BD58E6C86") print(sha256(master_key).hexdigest()) # cb05d0fd5e76ba8ea88323fc5d3eefd09a78d8e2a5fd4955307b549657a31330

That is what happens when you have no clue what hexadecimal actually looks like. Thank you! Is there any chance you were ever part of the ArmA 2 community?

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