Json Parsing Swift 3 Alamofire

Question

I am new at Swift 3 and I got problems with getting Json return then sending request. I am trying to send a post request to the server with parameters username and password and get a response with Json with information, but I haven't been able to get the data to return.

Output:

error: NSURLErrorDomain: -1003 status code: 200, headers Connection = close; "Content-Type" = "application/json"; "Transfer-Encoding" = Identity

request on Android looks like:

 "{\n" + " \"jsonrpc\": \"2.0\",\n" + " \"id\": \"1\",\n" + " \"method\": \"call\",\n" + " \"params\": [\n" + " \"" + LOGIN_TOKEN + "\",\n" + " \"session\",\n" + " \"login\",\n" + " {\n" + " \"username\": \"" + userName + "\",\n" + " \"password\": \"" + password + "\"\n" + " }\n" + " ]\n" + "}";

this is what I should send to request:

"{ \"jsonrpc\": \"2.0\", \"id\": 1, \"method\": \"call\", \"params\": [ \"00000000000000000000000000000000\", \"session\", \"login\", { \"username\": \"root\", \"password\": \"admin01\" } ] }"

This is my code:

 override func viewDidLoad() { var userName = "root" var password = "admin01" //var LOGIN_TOKEN = 0000000000000000 let jsonObject: [String: Any] = ["jsonrpc" : 2.0, "id": 1, "method": "call", "params": [ "00000000000000", "session", "login", [ "username": userName, "password": password]], ] do { let jsonData = try JSONSerialization.data(withJSONObject: jsonObject, options: .prettyPrinted) // here "jsonData" is the dictionary encoded in JSON data let decoded = try JSONSerialization.jsonObject(with: jsonData, options: []) // here "decoded" is of type `Any`, decoded from JSON data // you can now cast it with the right type if let dictFromJSON = decoded as? [String:String] { // use dictFromJSON } } catch { print(error.localizedDescription) } Alamofire.request("http://192.168.1.1/ubus", method: .post, parameters: jsonObject, encoding: JSONEncoding.default) .responseJSON { response in print(response) //to get status code if let status = response.response?.statusCode { switch(status){ case 201: print("example success") default: print("error with response status: \(status)") } } //to get JSON return value if let result = response.result.value { let JSON = result as! NSDictionary print(JSON) } } super.viewDidLoad() // Do any additional setup after loading the view, typically from a nib. } override func didReceiveMemoryWarning() { super.didReceiveMemoryWarning() // Dispose of any resources that can be recreated. }

try using SwiftyJSON github.com/SwiftyJSON/SwiftyJSON

JuicyFruit
– JuicyFruit

2017-01-10 18:53:06 +00:00
Commented Jan 10, 2017 at 18:53 — JuicyFruit
– JuicyFruit, Commented Jan 10, 2017 at 18:53

Pierce · Accepted Answer · 2017-01-10 19:10:59Z

Your JSON object seems to be invalid

There are really helpful JSON validators that are free. One that comes to mind is http://jsonlint.com

I think, from what I can interpret by the code you posted, that you want your jsonObject to look something like this, which is a valid JSON:

[ { "jsonrpc": 2.0, "id": 1, "method": "call", "params": ["00000000000000", "session", "login"], "username": username, "password": password } ]

I assume the username and password variables are strings you have already assigned?

I got some errors. After "jsonrpc" need ; and any type cant be used with arrays, I got request onAndroid studio and its working perfectly.
@GediminasUrbonas - That's because it's JSON code, and you're trying to make it a Swift object. You should look into creating a JSON file with the above code, and then learn how to convert JSON to Data. You can't just cast JSON code as Swift Data, it has to be converted somehow.

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