Using this code:
import random import query import sys while True: try: number = int(input('Choose a number between 0 and 10:')) except ValueError: print("That is not a number.") continue if number > 10: print('Your number is too large.') continue elif number < 0: print('Your number is too small.') continue break result = random.randint(0, 10) print("You're number: " + str(number)) print("Our number: " + str(result)) if number == result: print('Congratulations!') else: print('Close, but no cigar.') while True: try: answer = query.query_yes_no('Do you wish to contunue?') if answer == "yes": while True: try: number = int(input('Choose a number between 0 and 10:')) except ValueError: print("That is not a number.") continue if number > 10: print('Your number is too large.') continue elif number < 0: print('Your number is too small.') continue break print("You're number: " + str(number)) print("Our number: " + str(result)) if number == result: print('Congratulations!') continue else: print('Close, but no cigar.') continue elif answer == "no": print('Goodbye.') break break break exit() I keep getting a SyntaxError: unexpected EOF while parsing. It says it is on line 60. I have tried removing the exit() and the breaks but that doesn't work. I'm sure it is something simple as I am still new to Python. Any help would be greatly appreciated!
