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If I try to deserialize a JSON string that is missing a field from the object class, that field is set to null when the object is created. I need Jackson to throw an exception when this happens so I don't have to implement an assertNotNullFields() method in every object; i.e the JSON string input must have defined all the fields in the class or a JsonProcessingException is thrown.

Object mapper configuration:

objectMapper.setVisibility(PropertyAccessor.ALL, JsonAutoDetect.Visibility.NONE); objectMapper.setVisibility(PropertyAccessor.FIELD, JsonAutoDetect.Visibility.ANY);

JSON object:

public class LogInUser { public String identifier, password; public LogInUser() {} }

Is this possible given my configuration?

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You could try using JsonCreator within your LogInUser class as mentioned here. When introduced into the code you posed in your quesion, it would look something like this:

public class LogInUser { @JsonCreator public LogInUser(@JsonProperty(value = "identifier", required = true) String identifier, @JsonProperty(value = "password", required = true) String password) { this.identifier = identifier; this.password = password; } public String identifier, password; public LogInUser() {} }

When one or more of the values are null, it should throw an exception.

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