How to add a character in a predefined string?

Question

I made a function that separates one of my data points to eliminate a character.I want to add R: G: B: into the 3 numbers. So for example if the values are 255,0,0 than it becomes

255 0 0

I want it to be

R:255 G:0 B:0

This is the function I made to separate the commas.

#include string void RGB(string input) { istringstream ssString(input); while (getline(ssString, input, ',')) cout<< input << endl; }

Keep track of which line you're reading and append R, G or B accordingly. Also try and use const string& input in your signature, it helps avoid unnecessary copying. — tadman
– tadman, Commented Apr 6, 2017 at 1:34
@tadman I have tried to do that but since its in a while loop it just repeats those characters, so if I only had to do R: I would be fine but every iteration has to be different and I don't know how to implement that. — Rafael
– Rafael, Commented Apr 6, 2017 at 1:41

paddy · Accepted Answer · 2017-04-06 01:47:27Z

You can just iterate through an array of your prefixes. Something like this would be sufficient.

const char *prefix[3] = { "R:", "G:", "B:" }; for( int p = 0; p < 3 && getline(ssString, input, ','); p++ ) { cout << prefix[p] << input << endl; }

andria_girl · Accepted Answer · 2017-04-06 03:36:17Z

A way to do this without adding or subtracting lines from your code would be:

 int c = -1; // counter while(std::getline(ssString, input, ',')) std::cout << (++c == 0 ? 'R' : c == 1 ? 'G' : 'B') << ": " << input << std::endl; return 0;

The ternary operator utilizes a counter variable that starts at -1, the ternary eliminates the need for several if statements. Note: you have to wrap the ternary in parenthesis ( ) otherwise the compiler throws errors at you.

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