How to Parse SoapFaultClientException in spring-ws

Question

I am using spring-ws-2.3.1, While creating client for webservices sometime i am getting SoapFaultClientException like below,

<SOAP-ENV:Body> <SOAP-ENV:Fault> <faultcode>SOAP-ENV:Server</faultcode> <faultstring>There was a problem with the server so the message could not proceed</faultstring> <faultactor>InvalidAPI</faultactor> <detail> <ns0:serviceException xmlns:ns0="http://www.books.com/interface/v1"> <ns1:messageId xmlns:ns1="http://www.books.org/schema/common/v3_1">5411</ns1:messageId> <ns1:text xmlns:ns1="http://www.books.org/schema/common/v3_1">Locale is invalid.</ns1:text> </ns0:serviceException> </detail> </SOAP-ENV:Fault>

I am trying to get the "messageId" and "Text" of the ServiceException but i couldn't.Please find the code below,

catch (SoapFaultClientException ex) { SoapFaultDetail soapFaultDetail = ex.getSoapFault().getFaultDetail(); // <soapFaultDetail> node // if there is no fault soapFaultDetail ... if (soapFaultDetail == null) { throw ex; } SoapFaultDetailElement detailElementChild = soapFaultDetail.getDetailEntries().next(); Source detailSource = detailElementChild.getSource(); Object detail = webServiceTemplate.getUnmarshaller().unmarshal(detailSource); System.out.println("Detail"+detail.toString());//This object prints the jaxb element }

The "detail" object returns the JaxbElement.Is there any elegant way to parse the soap fault.

Any help should be appreciated.

VelNaga · Accepted Answer · 2017-04-11 08:13:15Z

Finally,I can able to parse the soap fault exception,

catch (SoapFaultClientException ex) { SoapFaultDetail soapFaultDetail = ex.getSoapFault().getFaultDetail(); // <soapFaultDetail> node // if there is no fault soapFaultDetail ... if (soapFaultDetail == null) { throw ex; } SoapFaultDetailElement detailElementChild = soapFaultDetail.getDetailEntries().next(); Source detailSource = detailElementChild.getSource(); Object detail = webServiceTemplate.getUnmarshaller().unmarshal(detailSource); JAXBElement<serviceException> source = (JAXBElement<serviceException>)detail; System.out.println("Text::"+source.getText()); //prints : Locale is invalid. }

I don't find any other elegant way so i hope this should be the solution.

You can void the unchecked cast (JAXBElement<serviceException>)detail by 1. casting to JAXBElement<?> - 2. calling detail.getValue() - 3. cast detail.getValue() to serviceException

Fozix · Accepted Answer · 2020-01-06 15:38:02Z

Did it this way, without unmarshaller.

 String DETAIL_PATH = "//*[local-name()='Detail']"; SoapFaultDetail soapFaultDetail = ((SoapFaultClientException)exception).getSoapFault().getFaultDetail(); DOMSource sourceNode = (DOMSource) soapFaultDetail.getSource(); XPath xPath = XPathFactory.newInstance().newXPath(); XPathExpression exp = null; //Cibling detail field try { exp = xPath.compile(DETAIL_PATH); NodeList nl = (NodeList) exp.evaluate(sourceNode.getNode(), XPathConstants.NODESET); if (nl == null || nl.getLength() < 1) { return; } else { //Get value here String detailValue = nl.item(0).getTextContent(); } } catch (XPathExpressionException e) { LOG.debug("Can't get detail from Exception"); }

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