Filter unique values from an array of objects [duplicate]

Question

How can I use Array.filter() to return unique id with name ?

My scenario is slightly different than the solutions I have researched in that I have an array of objects. Every example I find contains a flat array of single values.

data=[ {id: 555, name: "Sales", person: "Jordan" }, {id: 555, name: "Sales", person: "Bob" }, {id: 555, name: "Sales", person: "John" }, {id: 777, name: "Accounts Payable", person: "Rhoda" }, {id: 777, name: "Accounts Payable", person: "Harry" }, {id: 888, name: "IT", person: "Joe" }, {id: 888, name: "IT", person: "Jake" }, ];

var unique = data.filter( function (x, i) { return data[i].id.indexOf(x.id) === i });

Thanks in advance.

Mamun · Accepted Answer · 2019-02-07 13:05:16Z

I think forEach() is better to achieve what you are looking for:

var data=[ {id: 555, name: "Sales", person: "Jordan" }, {id: 555, name: "Sales", person: "Bob" }, {id: 555, name: "Sales", person: "John" }, {id: 777, name: "Accounts Payable", person: "Rhoda" }, {id: 777, name: "Accounts Payable", person: "Harry" }, {id: 888, name: "IT", person: "Joe" }, {id: 888, name: "IT", person: "Jake" }, ]; var resArr = []; data.forEach(function(item){ var i = resArr.findIndex(x => x.name == item.name); if(i <= -1){ resArr.push({id: item.id, name: item.name}); } }); console.log(resArr);

If you really want to use filter() try the following way:

var data=[ {id: 555, name: "Sales", person: "Jordan" }, {id: 555, name: "Sales", person: "Bob" }, {id: 555, name: "Sales", person: "John" }, {id: 777, name: "Accounts Payable", person: "Rhoda" }, {id: 777, name: "Accounts Payable", person: "Harry" }, {id: 888, name: "IT", person: "Joe" }, {id: 888, name: "IT", person: "Jake" }, ]; var resArr = []; data.filter(function(item){ var i = resArr.findIndex(x => x.name == item.name); if(i <= -1){ resArr.push({id: item.id, name: item.name}); } return null; }); console.log(resArr);

Yup, that's it ! I was going for a for loop, but I think filter is best.
I don't understand why SO jumps to conclusions so quickly re: with a duplicate answer remark. I had searched, but hadn't found the best solution for my scenario.
I think that forEach would be better since this approach does not actually use the filter function, since it does not return anything inside the function.
data = data.reduce((items, item) => items.find(x => x.name === item.name) ? [...items] : [...items, item], [])
@jinglesthula my bad, use just items in the first ternary branch

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