How to determine colors in an Array in Java

answer cuz cannot comment.

If you think checking all r, g, b, and alpha will need too many process for processing and would take time. So you you are right. But you are wrong as this work will be as easy as ABC for a OpenCL/CUDA (or generally GPGPU) program for example.

One solution could be converting the RGB form to HSL form, and simply change the L to 100% and again convert back it to RGB
For example, given color [3,50,2] in rgb form, which could be a dark green, the HSL value is [119,96,20]
now change the L value to 100%, and convert back the value to RGB which is [14,255,10]. So now it's simply ready for your constraint check as you mentioned.

Another solution could be change the constraint value into something relative to min and max values of given color.
for example, don't assume the g must be over 200 to mark the color as green, instead finds the max and min of all r, g, and b values, and now check if the g is more than 70% of max value.
Sample(EDIT):
Given color value as [3,50,2]. Now instead of assume the min value for checking a color (here the const 200), finds the max value of given color (which is 50 here) and assume the min value 70%(or anything) of max val. check the sample below.

int given_color=0x00033202;//3,50,2 in ARGB form in hex int relative_max=(given_color&0xff);//not 200, default assume blue is max int relative_min=(given_color&0xff);//not 200, default assume blue is min int tmp; for(int a=8;a<=16;a+=8){//check for red and green too tmp=(given_color>>a)&0xff; if(tmp<relative_min){relative_min=tmp;} if(tmp>relative_max){relative_max=tmp;} }//now you have max and min of given color, here 50 and 2 //now assume the 74% of real max value is const val 200 //and the value you want to check for color relative_max*=0.74; relative_min*=0.74; //now check over real amx and rel min over const values if( (r<relative_min) && (g>relative_max) && (b>relative_max) ){}//could be cyan //...etc