How to access variable's value from base class in derived class?

Question

#include<iostream> class Foo { protected: // Make x visible to derived classes int x; public: Foo() { x = 2; } }; class Derived : public Foo { public: Derived() { x = 4; } void print(){ std::cout << x << std::endl; } }; int main() { Derived a; a.print(); }

This prints 4.I want to access both the values of x in print.I want to print 2 and 4 both.Do I need to creat object of Foo in Derived class and access it through object.x?But that calls the constructor of Foo more than once.I don't want that to happen.

"I want to print 2 and 4 both" - std::cout << 2 << 4 << '\n'? Seriously, what do you mean? — Christian Hackl
– Christian Hackl, Commented Apr 23, 2017 at 9:31

Sergei · Accepted Answer · 2017-04-23 09:35:56Z

2

You need two variables to hold two values.

answered Apr 23, 2017 at 9:35

Sergei

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Comments

Jesper Juhl · Accepted Answer · 2017-04-23 10:43:06Z

There is only one x in the object total. Not one in the Foo part and one in the Derived part. So when your Derived constructor assigns 4 to x then that is the value of the variable, period. If you need to hold two distinct values then you need two variables.

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