comparing one column in two spreadsheets in openpyxl

Question

I am making an excel comparing program but I seem to be stuck. I want to compare two excel files in a spreadsheet. Here is my code:

import openpyxl wb = openpyxl.load_workbook('C:\\Users\\Bill\\Desktop\\CK_Server_list_0.1.xlsx') ws = wb.active wb1 = openpyxl.load_workbook('C:\\Users\\Bill\\Desktop\\CK_Server_list_0.2.xlsx') ws1 = wb1.active for x in ws.iter_cols(max_col=1): for cell in x: print(cell.value, cell.coordinate) for row1 in ws1.iter_cols(min_col=1): if row1[0].value != ws.cell(row=x, column=1).value: print(str(row1[0].value) + ' is not equal to ' + str(ws.cell(row=x, column=1).value + ' ' + str(ws.cell(row=x, column=1).coordinate)))

And every time I run this it gives me an error saying that tuple() < int(). Can anyone fix this problem? Any help would be appreciated.

Are you attempting to compare a column from the first table (0.1.xlsx) to a row in the second (0.2.xlsx)? — njoosse
– njoosse, Commented May 25, 2017 at 18:41

Xukrao · Accepted Answer · 2017-05-26 14:06:36Z

This error pops up because your variable x contains a tuple of cell objects at the time when the line if row1[0].value != ws.cell(row=x, column=1).value: gets executed. The input argument row requires an int value instead.

I think that a good approach for your problem would be to use for loops in combination with zip statements (more on zip here):

import openpyxl wb = openpyxl.load_workbook('C:\\Users\\Bill\\Desktop\\CK_Server_list_0.1.xlsx') ws = wb.active wb1 = openpyxl.load_workbook('C:\\Users\\Bill\\Desktop\\CK_Server_list_0.2.xlsx') ws1 = wb1.active for (col, col_1) in zip(ws.iter_cols(), ws1.iter_cols()): for (cell, cell_1) in zip(col, col_1): if cell.value != cell_1.value: print(str(cell.value) + ' is not equal to ' + str(cell_1.value) + ' ' + str(cell.coordinate))

@bhushanpardhi The zip statement stops once the smallest input iterable is exhausted. Therefore this code will only compare the rows and columns that are present in both excel sheets.

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