Remove a line of characters in a String with Swift

Question

I read many questions about removing characters from a string. But none of them resolved my issue.

I have this string:

"\"iconCls\":X.net.RM.getIcon(\"BulletWhite\")"

I want to replace this part:

"X.net.RM.getIcon(\"BulletWhite\")"

By this (double quotes in fact):

"\"\""

I use this code:

let dataString = "\"iconCls\":X.net.RM.getIcon(\"BulletWhite\")" let newString = dataString?.replacingOccurrences(of: "X.net.RM.getIcon(\"BulletWhite\")" as String, with: "", options: .regularExpression, range: nil)

But it doesn't work. I can replace all characters until I want to replace strings containing parentheses.Any idea? Thanks!

rmaddy · Accepted Answer · 2017-06-01 17:23:09Z

You are passing the .regularExpression option but you are not actually using a regular expression.

Change:

.regularExpression

to:

[]

This gives the result you want:

let dataString = "\"iconCls\":X.net.RM.getIcon(\"BulletWhite\")" let newString = dataString.replacingOccurrences(of: "X.net.RM.getIcon(\"BulletWhite\")" as String, with: "", options: [], range: nil)

Output:

"icnCls":

Even simpler:

let newString = dataString.replacingOccurrences(of: "X.net.RM.getIcon(\"BulletWhite\")" as String, with: "")

José Neto · Accepted Answer · 2017-06-01 17:22:32Z

1

You don't need to use options or range for this.

let str = "\"iconCls\":X.net.RM.getIcon(\"BulletWhite\")" let replace = "X.net.RM.getIcon(\"BulletWhite\")" let replaceBy = "\"\"" let newString = str.replacingOccurrences(of: replace, with: replaceBy)

answered Jun 1, 2017 at 17:22

José Neto

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4 Comments

Paul Bénéteau Over a year ago

But how can I convert it to remove backslash before double quotes? Is this an encoding format?

rmaddy Over a year ago

@greenpoisononeTV There are no backslashes in the actual string. There's nothing to remove.

Paul Bénéteau Over a year ago

@rmaddy Of course there are backslashes before all double quotes when I print the string.

rmaddy Over a year ago

@greenpoisononeTV That's just Xcode's debug output. If you put that string in a label, for example, there would be no backslashes. To be clear, I am referring to the values in the code posted in your question and the answers.

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