Class conforming to protocol as function parameter in Swift Error

Question

I'm currently in Swift 3.1 and the following code does not compile.

protocol HeaderDisplayable { func setTitle(_ string: String) } class MyView: UILabel, HeaderDisplayable { func setTitle(_ string: String) { self.text = string } } func foo<T: UILabel>(view:T) where T: HeaderDisplayable{ view.setTitle("HEY") } foo(MyView())

The error message is saying

Generic parameter 'T' could not be inferred

Martin R · Accepted Answer · 2017-06-07 07:55:41Z

The error is a bit misleading but you are missing the argument label. You need to do this:

foo(view: MyView())

or if you want to remove the need for it you could change the method definition to this:

func foo<T: UILabel>(_ view:T) where T: HeaderDisplayable{ view.setTitle("HEY") }

Either version will work fine.

Ha that was stupid of me! The error message did not help at all

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