Embedding Video File in Django Site

There are two ways you can do this -

Method 1: Pass parameter in URL and display video based on that parameter -

If you don't want to use models at any cost, use this, else try method 2.

Assuming you have saved all videos in your media directory and they all have unique names (serving as their ids).

your_app/urls.py -

from django.conf.urls import url from . import views urlpatterns = [ url(r'^video/(?P<vid>\w+)/$',views.display_video) # \w will allow alphanumeric characters or string ] 

Add this in the project's settings.py -

#Change this as per your liking MEDIA_URL = '/media/' MEDIA_ROOT = os.path.join(BASE_DIR, 'media') 

your_app/views.py -

from django.conf import settings from django.shortcuts import render from django.http import HttpResponse import os import fnmatch def display_video(request,vid=None): if vid is None: return HttpResponse("No Video") #Finding the name of video file with extension, use this if you have different extension of the videos video_name = "" for fname in os.listdir(settings.MEDIA_ROOT): if fnmatch.fnmatch(fname, vid+".*"): #using pattern to find the video file with given id and any extension video_name = fname break ''' If you have all the videos of same extension e.g. mp4, then instead of above code, you can just use - video_name = vid+".mp4" ''' #getting full url - video_url = settings.MEDIA_URL+video_name return render(request, "video_template.html", {"url":video_url}) 

Then in your template file, video_template.html, display video as -

<video width="400" controls> <source src="{{url}}" type="video/mp4"> Your browser does not support HTML5 video. </video> 

Note: There can be performance issue, iterating through all the files in the folder using os.listdir(). Instead, if possible, use a common file extension or use the next method (strongly recommended).

Method 2 : Storing video ids and correspondig file names in database -

Use same settings.py, urls.py and video_template.html as in method 1.

your_app/models.py -

from django.db import models class videos(models.Model): video_id = models.CharField(blank=False, max_length=32) file_name = models.CharField(blank=False, max_length=500) def __str__(self): return self.id 

your_app/views.py -

from django.conf import settings from django.shortcuts import render, get_object_or_404 from django.http import HttpResponse from .models import videos def display_video(request,vid=None): if vid is None: return HttpResponse("No Video") try: video_object = get_object_or_404(videos, pk = vid) except videos.DoesNotExist: return HttpResponse("Id doesn't exists.") file_name = video_object.file_name #getting full url - video_url = settings.MEDIA_URL+file_name return render(request, "video_template.html", {"url":video_url}) 

So if you want to access any page with video id 97veqne0, just goto - localhost:8000/video/97veqne0