I have a two dimensional hashes in Ruby.
h = { "a" => {"v1" => 0, "v2" => 1}, "c" => {"v1" => 2, "v2" => 3} } I would like to delete those elements from the hash, where value 1 (v1) is 0, for example, so my result would be:
{ "c" => {"v1" => 2, "v2" => 3} } I wanted to achieve this by iterating trough the hash with delete_if, but I'm not sure how to handle the nested parts with it.
Is that what you're looking for?
h.delete_if { |_, v| v['v1'].zero? } #=> {"c" => {"v1" => 2, "v2" => 3}} As @TomLord says, it also may be variant, when v1 can be not defined or equal to nil, in this case, it would be better to use v['v1'] == 0
'v1' key, and will it always map to Numeric object? If not, it would be safer to use == 0 instead of .zero?.You can use Hash#value? in your block to check if any of the values in the nested hashes equal 0:
hash.delete_if { |k,v| v.value? 0 } #=> { "c" => { "v1" => 2, "v2" => 3 } } 
v1 in the sub hash so if v1 == 1 and v2 == 0 then this solution is inaccurate