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jqlib.js is https://code.jquery.com/jquery-3.2.1.js

nothing is happing i m trying to add to number using ajax using jquery 3.2.1.js

cant find the error in this code can anyone tell me where is the error in this code

add.php

<html> <body> <script type="text/javascript" src="jqlib.js"></script> <form id="tt"> <table> <tr> <td>Enter first Number</td> <td><input type=text name=t1 ></td> </tr> <tr> <td>Enter 2nd Number</td> <td><input type=text name=t2></td> </tr> <tr> <td><input type=button value="OK" onClick="cal()"></td> </tr> <tr> <td>Addition</td> <td><input type=text name=t3 id="tt1"></td> </tr> </table> </form> </body> </html> <script type="text/javascript"> function cal() { var frm = $("#tt"); $.ajax( { type:"POST", url:"ajax.php", data:frm.serialize(), sucess:function (data) { $("#tt1").val(data); } }); } </script> 

ajax.php

<?php if(!empty($_POST)) { if(($_POST['t1']!="" )|| ($_POST['t2']!="")) { $z = $_POST['t1'] + $_POST['t2']; } else { $z ="please enter data"; } echo $z; } else { echo "please enter data"; } ?> 
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  • blank nothing is showing Commented Jul 1, 2017 at 12:42
  • check @SepehrRaftari 's answer Commented Jul 1, 2017 at 12:43
  • @AyushmanKasyap check SepehrRaftari's answer, and if it helps, upvote and accept it. Commented Jul 1, 2017 at 12:43

2 Answers 2

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you have a typo error: sucess should be success

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Comments

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Change your script as follow and check whether any alert is showing or not

<script type="text/javascript"> function cal() { var frm = $("#tt"); $.ajax( { type:"POST", url:"ajax.php", data:frm.serialize(), sucess:function (data) { $("#tt1").val(data); alert('Success: '+data); ///---> this show alert with success and content }, error:function(a,b,c) { alert(c); //---> If error happen it will show alert(); } }); } </script> 

2 Comments

check your browser console. It will show any jquery error in it
@Fairy requesting a clarification from OP would be a fine comment methinks, but not answer material. Anyways, you also duplicated OP's typo.

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