Endianess Related to processor or data type

Question

I am working with little endian processor PIC 32 and am looking at a variable that is of type BOOL. One variable is initialized to TRUE and the other as false.

static BOOL A = TRUE; BOOL static B = FALSE;

In Memory when I look in memory for variable A, it shows

It looks like the processor just assigns a 32 bit number for true and false and not 8 bits so that means its processor dependent. For an array of 6 elements of type BOOL, all set to TRUE. How would it be read? Is it going to show up as 6 elements of what is shown in the picture above?

How do you know it allocates 32-bits? That looks like an 8-bit bool followed by three other things that are zero, like B being false. — tadman
– tadman, Commented Jul 5, 2017 at 21:48
C doesn't define a type BOOL. It defines _Bool, and stdbool.h defines bool. What does your BOOL typedef look like? — Barmar
– Barmar, Commented Jul 5, 2017 at 22:00
Although you are allowed (at the moment) to write int long unsigned const long static u = 23;, you shouldn't do that. Interestingly, GCC 7.1.0 when run with -Werror -Wold-style-declaration doesn't allow it: error: ‘static’ is not at beginning of declaration [-Werror=old-style-declaration]. (And -Wextra includes -Wold-style-declaration (at least in GCC 7.1.0), so you don't have to add it separately.) — Jonathan Leffler
– Jonathan Leffler, Commented Jul 5, 2017 at 22:21

chqrlie · Accepted Answer · 2017-07-05 22:08:59Z

BOOL is not a standard type. Depending on how it is defined in your environment, probably via a typedef in a header file, it may be any integer type, including unsigned char which would use 1 byte or int which may use 4 bytes on your system and other sizes for other architectures.

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Endianess Related to processor or data type

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