I tried using the np.isin() function but everytime I do, it returns me the error:
AttributeError: 'module' object has no attribute 'isin' here is exactly what I do
import numpy as np a = np.arange(9).reshape((3,3)) test = np.arange(5) print np.isin(a, test) I havent found any information about this problem, I use the latest version of numpy and havent had any problem with other numpy module, why does it returns me this error?
The isin function was added in NumPy 1.13:
New
np.isinfunction, improves onin1d.
You're probably using an older version.
Reading through the Notes section of the docs shows
New in version 1.13.0.
I suspect that if you do
print(np.__version__) you will see something less than 1.13.0.
Following the [source] link in the docs I find that:
def isin(element, test_elements, assume_unique=False, invert=False): "..." element = np.asarray(element) return in1d(element, test_elements, assume_unique=assume_unique, invert=invert).reshape(element.shape) It's not doing anything that you can't already do with in1d.
The containing file can be downloaded, and used from your own directory. It has an enhanced unique.
np.sin()?np.isin. @Tissuebox It works for me in Python3.