Form a sequence of integers at specified interval in bash

Question

I create a sequence with interval 1 using {0..4} syntax alright:

$ for i in {0..4}; do echo $i; done 0 1 2 3 4

However, when I set interval explicitly at 2 using conventional syntax {0..4..2}, it doesn't work:

$ for i in {0..4..2}; do echo $i; done {0..4..2}

And the expected output should be:

0 2 4

My bash version:

$ echo ${BASH_VERSION} 3.2.25(1)-release

Any feedback is appreciated!

e0k · Accepted Answer · 2017-07-15 01:16:21Z

1

You could use the syntax:

$ for ((i=0; i<=4; i+=2)); do echo $i; done

answered Jul 15, 2017 at 1:16

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Comments

Dan Kreiger · Accepted Answer · 2017-07-15 01:05:41Z

0

$ for i in `seq 0 2 4`; do echo $i; done

answered Jul 15, 2017 at 1:05

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Nice and simple. Thank you! ...Still wondering why {0..4..2} is not working.

@koch No problem! From what I know, that curly brace step syntax only works in zsh, ksh93, and I believe bash 4+.