Java - Changing variable value without accessing it

Question

I want to change the variable value without changing it directly, In C or C++ we may use pointers or reference variable to do that since no pointer concept in java, how we can do that.
in C we may do like this

int var=10; int *ptr; ptr=&var; *ptr++; printf("%d",var);

output :11
Is there is any other way to do same thing in java ?

Thanks in advance.

In Java everything is a reference (slap me if I'm slightly off). — Tim Biegeleisen
– Tim Biegeleisen, Commented Jul 24, 2017 at 11:38
Java has pointers, but you cannot manipulate them like in C++ or C — Kenneth Clark
– Kenneth Clark, Commented Jul 24, 2017 at 11:39
@TimBiegeleisen can you please give me simple code snippet using reference.please — Raj kumar
– Raj kumar, Commented Jul 24, 2017 at 11:39

CodedStingray · Accepted Answer · 2017-07-24 11:47:36Z

3

All the primitive types in Java (byte, short, int, long, float, double, boolean, char) are call by value, so with these, no, you can't do it. You can do it with objects though, as those are references.

Example:

public class MyInt { public int value; } public static void main(String args[]) { MyInt i1 = new MyInt(); i1.value = 2; MyInt i2 = i1; i2.value++; System.out.println(i1.value); }

edited Jul 24, 2017 at 11:47

answered Jul 24, 2017 at 11:41

CodedStingray

3911 silver badge10 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

Tim Over a year ago

your example is missing

CodedStingray Over a year ago

sorry messed up, added it now ^^

Raj kumar Over a year ago

Example please.

Tim Over a year ago

what does it print?

CodedStingray Over a year ago

it prints 3, as bothi1 and i2 are references to the same object

Collectives™ on Stack Overflow

Java - Changing variable value without accessing it

1 Answer 1

5 Comments

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

5 Comments

Linked

Related