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I am parsing some XML something like this:

<root> <some_gunk/> <dupe_node> ... stuff I want ... </dupe_node> <bits_and_pieces/> <other_gunk/> <dupe_node> ... stuff I don't want ... </dupe_node> <more_gunk/> </root> 

An XPath of '//dupe_node' will give me two instances of dupe_node to play with. I only want to traverse the first. Can I do this with XPath?

3 Answers 3

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/descendant::dupe_node[1] 

//dupe_node[1] is generally wrong, although it produces an identical result in this particular case. See docs:

The location path //para[1] does not mean the same as the location path /descendant::para[1]. The latter selects the first descendant para element; the former selects all descendant para elements that are the first para children of their parents.

Given the following XML:

<foo> <bar/> <foo> <bar/> </foo> </foo> 

//bar[1] will produce two nodes, because both bars are first children of their respective parents.

/descendant::bar[1] will give only one node, which is the first of all the bars in the document.

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1 Comment

So how do you write it if you want the first node that is a descendant or self? /descendant::dupe_node[1] excludes self right?
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//dupe_node[1] 

XPath counts from 1, not 0 in this case. You can use this tool to try things out in your browser:

http://www.xmlme.com/XpathTool.aspx?mid=82

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//dupe_node[1]

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