In Java, how to get all groups which is inside a group (regular expression).
For example:Using (([A-Z][a-z]+)+)([0-9]+) test a string : "AbcDefGhi12345".
Then get Result:
matches():yes
groupCount():3
group(1):AbcDefGhi
group(2):Ghi
group(3):12345
But I want to get String "Abc", "Def", "Ghi", "12345" respectively.
How can I do that by using regular expression?
Regular expressions cannot handle repeating groups it can return any of the captured groups (in your case it returned "Ghi").
The example below will print:
Abc Def Ghi 12345 The code:
public static void main(String[] args) { String example = "AbcDefGhi12345"; if (example.matches("(([A-Z][a-z]+)+)([0-9]+)")) { Scanner s = new Scanner(example); String m; while ((m = s.findWithinHorizon("[A-Z][a-z]+", 0)) != null) System.out.println(m); System.out.println(s.findWithinHorizon("[0-9]+", 0)); } } 
Pattern p = Pattern.compile("([A-Z][a-z]+|(?:[0-9]+))"); Matcher m = p.matcher("AbcDefGhi12345"); while(m.find()){ System.out.println(m.group(1)); } 
[A-Z][a-z]+ is okey it is the best solution!like hzh's answer with some format and a little bit simpler:
Pattern p = Pattern.compile("[A-Z][a-z]+|[0-9]+"); Matcher m = p.matcher("AbcDefGhi12345"); while(m.find()){ System.out.println(m.group(0)); } gives you
Abc Def Ghi 12345