I want to run a command in Swift using Process. This is my current code:
process.launchPath = "/bin/sh" process.arguments = ["symbolicatecrash", "crash.crash"] However, this executes the command as sh symbolicatecrash crash.crash. I want this command to be executed as ./symbolicatecrash crash.crash. How can I achieve the same in Swift.
I tried the following code (which is a run time crash)
process.launchPath = "" process.arguments = ["symbolicatecrash", "crash.crash"] Simple: when you want to be in full control of the path to be used - simply specify an absolute path for example, like:
process.arguments = ["/usr/bin/symbolicatecrash", "crash.crash"] or where ever that script is located.
Beyond that: keep in mind that "./" as relative path depends on the context of your application.
In that sense: you could have a look here to understand how to actually "implement" relative paths - to then use that knowledge to create an absolute path that matches the desired relative path yourself.
But given the comment, the most "simple" answers seems to be:
process.launchPath = "usr/bin/env" process.arguments = ["./symbolicatecrash", "crash.crash"] i 
process.launchPath = "usr/bin/env" process.arguments = ["./symbolicatecrash", "crash.crash"] is the right way to run this. Since your answer closely matches, please update this, post which I can mark this as correct. It is important to do it this way because without providing launchPath, application would crash at run time.