I have the following code
value1: string; value2: string; ... activate(): Promise<any> { return Promise.all([ this.promise1().then(value1 => this.value1 = value1), this.promise2().then(value2 => this.value2 = value2) ]); } Is there a convenience method for something like this?
I tried the following but did not work as I had hoped
return Promise.all([ this.value1 = this.promise1().value(), this.value2 = this.promise2().value() ]); Use single then callback and destructuring assignment syntax, and initialize value1, value2 there:
activate(): Promise<any> { return Promise .all([ this.promise1(), this.promise2() ]) .then([value1, value2] => { this.value1 = value1; this.value2 = value2; }); } There may already be such a convenience method in bluebird, not sure, but I wrote my own that seems to do what you want
const objectPromise = obj => { const keys = Object.keys(obj); return Promise.all(Object.values(obj)).then(results => Object.assign({}, ...results.map((result, index) => ({[keys[index]]: result})))); }; To use it
value1: string; value2: string; ... activate(): Promise<any> { return objectPromise({value1: this.promise1, value2: this.promise2()}) .then(results => Object.assign(this, results)); } On searching Bluebird documentation, I came across Promsie.props
So
value1: string; value2: string; ... activate(): Promise<any> { return Promise.props({value1: this.promise1, value2: this.promise2()}) .then(results => Object.assign(this, results)); } should do what you want
